This question is a little technical but I feel someone here may be able to help me with my understanding of trigger work.
Just how does reducing the hammer hook/sear engagement adjust trigger pull?
My physics books tell me that when dealing with friction, that if it takes X amount of force to move an object, no matter what we do to the area providing the friction, friction will remain the same. In other words, if I have a box 2' wide x 3' long x 2' high setting on the floor so that the 2'x3' area is on the floor and it takes 75# of force to move it, the same box stood on end so the area is now 2'x2', the force to move it will remain the same 75#.
This would only be true if the hammer hook/sear was mated perfectly. I doubt that any hammer/sear meets perfectly, and even if it did, the sear rotates around the sear pin and the surfaces would move out of this perfect mating and throws the whole equation out the window.
So I'm back to the original question. How does reducing the sear/hammer engagement change trigger pull?
Anyone have an answer?
Douglas
Bookmarks